20m^2-212m+120=

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Solution for 20m^2-212m+120= equation:


Simplifying
20m2 + -212m + 120 = 0

Reorder the terms:
120 + -212m + 20m2 = 0

Solving
120 + -212m + 20m2 = 0

Solving for variable 'm'.

Factor out the Greatest Common Factor (GCF), '4'.
4(30 + -53m + 5m2) = 0

Factor a trinomial.
4((3 + -5m)(10 + -1m)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(3 + -5m)' equal to zero and attempt to solve: Simplifying 3 + -5m = 0 Solving 3 + -5m = 0 Move all terms containing m to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5m = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -5m = 0 + -3 -5m = 0 + -3 Combine like terms: 0 + -3 = -3 -5m = -3 Divide each side by '-5'. m = 0.6 Simplifying m = 0.6

Subproblem 2

Set the factor '(10 + -1m)' equal to zero and attempt to solve: Simplifying 10 + -1m = 0 Solving 10 + -1m = 0 Move all terms containing m to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1m = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1m = 0 + -10 -1m = 0 + -10 Combine like terms: 0 + -10 = -10 -1m = -10 Divide each side by '-1'. m = 10 Simplifying m = 10

Solution

m = {0.6, 10}

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